find distance only section 4 Practice Questions Answers Test with Solutions & More Shortcuts

Question : 16 [SSC CHSL LDC, DEO & PA/SA 2015]

Q walked 20 m towards west, took a left turn and walked 20 m. He then took a right turn and walked 20 m and again took a right turn and walked 20 m. How far is Q now from the starting point ?

a) 40 m

b) 80 m

c) 120 m

d) 50 m

Answer: (a)

direction-and-distance-verbal-reasoning

AE = AB + BE

= (20 + 20) metres

= 40 metres

Question : 17

A person starts from a point and goes 6 km in north direction. Now he takes a right turn and moves 7 km. Next he takes a left turn and moves 10 km. Next he turns right and moves 5 km. Finally he turns right and moves 12 km to reach his destination. Find the distance from his starting point.

a) $4√10 km$

b) $5√5 km$

c) 12 km

d) $6√2 km$

e) None of these

Answer: (a)

Required distance is $√(12^2 + 4^2 ) = 4√10 km$.

Question : 18

Kashish goes 30 metres North, then turns right and walks 40 metres, then again turns right and walks 20 metres, then again turns right and walks 40 metres. How many metres is he from his original position?

a) 10

b) 40

c) 0

d) 20

Answer: (a)

direction-and-distance

The movements of Kashish are as shown in figure (A to B, B to C, C to D, D to E).

So, Kashish’s distance from his original position A = AE

AE = (AB – BE) = (AB – CD) = (30 – 20) m = 10 m.

Question : 19

travelled from a point X straight to Y at a distance of 80 metres. He turned right and walked 50 metres, then again turned right and walked 70 metres. Finally, he turned right and walked 50 metres. How far is he from the starting point ?

a) 50 metres

b) 20 metres

c) 10 metres

d) 70 metres

e) None of these

Answer: (c)

direction-and-distance-verbal-reasoning

The movements of Raj are as shown in the figure,

(X to Y, Y to A, A to B, B to C)

∴  Raj's distnace from the starting point X

= XC = (XY - YC)

= (XY - BA)

= (80 - 70) = 10m.

Question : 20

Gaurav walks 20 metres towards North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is he from his original position ?

a) 50 metres

b) 30 metres

c) 20 metres

d) 60 metres

e) None of these

Answer: (d)

direction-and-distance-verbal-reasoning

The movements of Gaurav are as shown in Figure.

Clearly, Gaurav's distance from his initial position

P = PX = (PS + SX) = (QR + SX)

= (40 + 20)m = 60m.

IMPORTANT verbal reasoning EXERCISES

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920 direction & distance sense test based verbal reasoning section 4 question answer with explanation pdf

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