find distance only section 4 Practice Questions Answers Test with Solutions & More Shortcuts
direction & distance sense test PRACTICE TEST [15 - EXERCISES]
find directions only
find distance only
find both direction & distance
find directions only section 2
find directions only section 3
find directions only section 4
find directions only section 5
find directions only section 6
find distance only section 2
find distance only section 3
find distance only section 4
find distance only section 5
find distance only section 6
find both direction & distance section 2
find both direction & distance section 3
Question : 16 [SSC CHSL LDC, DEO & PA/SA 2015]
Q walked 20 m towards west, took a left turn and walked 20 m. He then took a right turn and walked 20 m and again took a right turn and walked 20 m. How far is Q now from the starting point ?
a) 40 m
b) 80 m
c) 120 m
d) 50 m
Answer »Answer: (a)
AE = AB + BE
= (20 + 20) metres
= 40 metres
Question : 17
A person starts from a point and goes 6 km in north direction. Now he takes a right turn and moves 7 km. Next he takes a left turn and moves 10 km. Next he turns right and moves 5 km. Finally he turns right and moves 12 km to reach his destination. Find the distance from his starting point.
a) $4√10 km$
b) $5√5 km$
c) 12 km
d) $6√2 km$
e) None of these
Answer »Answer: (a)
Required distance is $√(12^2 + 4^2 ) = 4√10 km$.
Question : 18
Kashish goes 30 metres North, then turns right and walks 40 metres, then again turns right and walks 20 metres, then again turns right and walks 40 metres. How many metres is he from his original position?
a) 10
b) 40
c) 0
d) 20
Answer »Answer: (a)
The movements of Kashish are as shown in figure (A to B, B to C, C to D, D to E).
So, Kashish’s distance from his original position A = AE
AE = (AB – BE) = (AB – CD) = (30 – 20) m = 10 m.
Question : 19
travelled from a point X straight to Y at a distance of 80 metres. He turned right and walked 50 metres, then again turned right and walked 70 metres. Finally, he turned right and walked 50 metres. How far is he from the starting point ?
a) 50 metres
b) 20 metres
c) 10 metres
d) 70 metres
e) None of these
Answer »Answer: (c)
The movements of Raj are as shown in the figure,
(X to Y, Y to A, A to B, B to C)
∴ Raj's distnace from the starting point X
= XC = (XY - YC)
= (XY - BA)
= (80 - 70) = 10m.
Question : 20
Gaurav walks 20 metres towards North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is he from his original position ?
a) 50 metres
b) 30 metres
c) 20 metres
d) 60 metres
e) None of these
Answer »Answer: (d)
The movements of Gaurav are as shown in Figure.
Clearly, Gaurav's distance from his initial position
P = PX = (PS + SX) = (QR + SX)
= (40 + 20)m = 60m.
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